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321310011404114 = 2160655005702057
BaseRepresentation
bin100100100001110101101000…
…1000101111010111101010010
31120010122221022010222120100222
41021003223101011322331102
5314103320400404412424
63055211440445113042
7124451611420643435
oct11103532105727522
91503587263876328
10321310011404114
11934198a09a2847
1230054048858782
1310a39533964135
14594b6b7acd81c
1527230264cbe5e
hex1243ad117af52

321310011404114 has 4 divisors (see below), whose sum is σ = 481965017106174. Its totient is φ = 160655005702056.

The previous prime is 321310011404059. The next prime is 321310011404131. The reversal of 321310011404114 is 411404110013123.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 189718530607225 + 131591480796889 = 13773835^2 + 11471333^2 .

It is a super-2 number, since 2×3213100114041142 (a number of 30 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80327502851027 + ... + 80327502851030.

Almost surely, 2321310011404114 is an apocalyptic number.

321310011404114 is a deficient number, since it is larger than the sum of its proper divisors (160655005702060).

321310011404114 is a wasteful number, since it uses less digits than its factorization.

321310011404114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160655005702059.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 321310011404114 its reverse (411404110013123), we get a palindrome (732714121417237).

The spelling of 321310011404114 in words is "three hundred twenty-one trillion, three hundred ten billion, eleven million, four hundred four thousand, one hundred fourteen".

Divisors: 1 2 160655005702057 321310011404114