Base | Representation |
---|---|
bin | 101110110000011100011… |
… | …001111111011111100011 |
3 | 102101011121022022022200220 |
4 | 232300130121333133203 |
5 | 410120423200104443 |
6 | 10500025555414123 |
7 | 451065625221123 |
oct | 56603431773743 |
9 | 12334538268626 |
10 | 3213112113123 |
11 | 1029745027600 |
12 | 43a8808b4343 |
13 | 1a3cc2515ba3 |
14 | b17305a8c83 |
15 | 588a8db3a83 |
hex | 2ec1c67f7e3 |
3213112113123 has 24 divisors (see below), whose sum is σ = 4709147941008. Its totient is φ = 1947289344000.
The previous prime is 3213112113121. The next prime is 3213112113149.
3213112113123 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3213112113123 - 21 = 3213112113121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3213112113093 and 3213112113102.
It is not an unprimeable number, because it can be changed into a prime (3213112113121) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17215383 + ... + 17401023.
It is an arithmetic number, because the mean of its divisors is an integer number (196214497542).
Almost surely, 23213112113123 is an apocalyptic number.
3213112113123 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3213112113123 is a deficient number, since it is larger than the sum of its proper divisors (1496035827885).
3213112113123 is a wasteful number, since it uses less digits than its factorization.
3213112113123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233347 (or 233336 counting only the distinct ones).
The product of its digits is 648, while the sum is 24.
The spelling of 3213112113123 in words is "three trillion, two hundred thirteen billion, one hundred twelve million, one hundred thirteen thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •