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32132011413 = 310710670471
BaseRepresentation
bin11101111011001101…
…111001010110010101
310001221100001022012210
4131323031321112111
51011301243331123
622432232304033
72215155406365
oct357315712625
9101840038183
1032132011413
1112699756837
126288b42019
133050cb0608
1417ab6689a5
15c80db5e93
hex77b379595

32132011413 has 4 divisors (see below), whose sum is σ = 42842681888. Its totient is φ = 21421340940.

The previous prime is 32132011393. The next prime is 32132011421. The reversal of 32132011413 is 31411023123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 32132011413 - 25 = 32132011381 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 32132011413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32132011013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5355335233 + ... + 5355335238.

It is an arithmetic number, because the mean of its divisors is an integer number (10710670472).

Almost surely, 232132011413 is an apocalyptic number.

It is an amenable number.

32132011413 is a deficient number, since it is larger than the sum of its proper divisors (10710670475).

32132011413 is a wasteful number, since it uses less digits than its factorization.

32132011413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10710670474.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 32132011413 its reverse (31411023123), we get a palindrome (63543034536).

The spelling of 32132011413 in words is "thirty-two billion, one hundred thirty-two million, eleven thousand, four hundred thirteen".

Divisors: 1 3 10710670471 32132011413