Base | Representation |
---|---|
bin | 1110100111001100110000… |
… | …00101110110010010110001 |
3 | 11012202220102002121212211121 |
4 | 13103212120011312102301 |
5 | 13202432244203330223 |
6 | 152201442245342241 |
7 | 6524355462326464 |
oct | 723463005662261 |
9 | 135686362555747 |
10 | 32133202011313 |
11 | a269683908507 |
12 | 372b768407981 |
13 | 14c11c006c2a0 |
14 | 7d13806952db |
15 | 3aacd1cb415d |
hex | 1d39981764b1 |
32133202011313 has 8 divisors (see below), whose sum is σ = 34647656320256. Its totient is φ = 29624843350800.
The previous prime is 32133202011311. The next prime is 32133202011419. The reversal of 32133202011313 is 31311020233123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 32133202011313 - 21 = 32133202011311 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32133202011311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1523901153 + ... + 1523922238.
It is an arithmetic number, because the mean of its divisors is an integer number (4330957040032).
Almost surely, 232133202011313 is an apocalyptic number.
It is an amenable number.
32133202011313 is a deficient number, since it is larger than the sum of its proper divisors (2514454308943).
32133202011313 is a wasteful number, since it uses less digits than its factorization.
32133202011313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3047824215.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 32133202011313 its reverse (31311020233123), we get a palindrome (63444222244436).
The spelling of 32133202011313 in words is "thirty-two trillion, one hundred thirty-three billion, two hundred two million, eleven thousand, three hundred thirteen".
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