Base | Representation |
---|---|
bin | 101110110000101001000… |
… | …011110011110101111101 |
3 | 102101012011002202201100120 |
4 | 232300221003303311331 |
5 | 410121342021331140 |
6 | 10500103021445153 |
7 | 451104113520222 |
oct | 56605103636575 |
9 | 12335132681316 |
10 | 3213324402045 |
11 | 102984394339a |
12 | 43a91ba107b9 |
13 | 1a40274b3834 |
14 | b1750869949 |
15 | 588bc8491d0 |
hex | 2ec290f3d7d |
3213324402045 has 8 divisors (see below), whose sum is σ = 5141319043296. Its totient is φ = 1713773014416.
The previous prime is 3213324402019. The next prime is 3213324402121. The reversal of 3213324402045 is 5402044233123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3213324402045 - 217 = 3213324270973 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3213324401997 and 3213324402015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107110813387 + ... + 107110813416.
It is an arithmetic number, because the mean of its divisors is an integer number (642664880412).
Almost surely, 23213324402045 is an apocalyptic number.
It is an amenable number.
3213324402045 is a deficient number, since it is larger than the sum of its proper divisors (1927994641251).
3213324402045 is a wasteful number, since it uses less digits than its factorization.
3213324402045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 214221626811.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 3213324402045 its reverse (5402044233123), we get a palindrome (8615368635168).
The spelling of 3213324402045 in words is "three trillion, two hundred thirteen billion, three hundred twenty-four million, four hundred two thousand, forty-five".
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