Base | Representation |
---|---|
bin | 101110110000101101100… |
… | …100111111111101100111 |
3 | 102101012100101102020002212 |
4 | 232300231210333331213 |
5 | 410122020423230203 |
6 | 10500114330354035 |
7 | 451106024060402 |
oct | 56605544777547 |
9 | 12335311366085 |
10 | 3213400211303 |
11 | 1029882711a77 |
12 | 43a94128b91b |
13 | 1a403a107599 |
14 | b175a960d39 |
15 | 588c43211d8 |
hex | 2ec2d93ff67 |
3213400211303 has 4 divisors (see below), whose sum is σ = 3217064294520. Its totient is φ = 3209736128088.
The previous prime is 3213400211221. The next prime is 3213400211317. The reversal of 3213400211303 is 3031120043123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3213400211303 - 224 = 3213383434087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3213400211353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1832040293 + ... + 1832042046.
It is an arithmetic number, because the mean of its divisors is an integer number (804266073630).
Almost surely, 23213400211303 is an apocalyptic number.
3213400211303 is a deficient number, since it is larger than the sum of its proper divisors (3664083217).
3213400211303 is an equidigital number, since it uses as much as digits as its factorization.
3213400211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3664083216.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 3213400211303 its reverse (3031120043123), we get a palindrome (6244520254426).
The spelling of 3213400211303 in words is "three trillion, two hundred thirteen billion, four hundred million, two hundred eleven thousand, three hundred three".
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