321400131433 has 4 divisors (see below), whose sum is σ = 322650715860. Its totient is φ = 320149547008.

The previous prime is 321400131421. The next prime is 321400131469. The reversal of 321400131433 is 334131004123.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 287796842089 + 33603289344 = 536467^2 + 183312^2 .

It is a cyclic number.

It is not a de Polignac number, because 321400131433 - 2⁵ = 321400131401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 321400131398 and 321400131407.

It is not an unprimeable number, because it can be changed into a prime (321400131133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 625291828 + ... + 625292341.

It is an arithmetic number, because the mean of its divisors is an integer number (80662678965).

Almost surely, 2^321400131433 is an apocalyptic number.

It is an amenable number.

321400131433 is a deficient number, since it is larger than the sum of its proper divisors (1250584427).

321400131433 is a wasteful number, since it uses less digits than its factorization.

321400131433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1250584426.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 321400131433 its reverse (334131004123), we get a palindrome (655531135556).

The spelling of 321400131433 in words is "three hundred twenty-one billion, four hundred million, one hundred thirty-one thousand, four hundred thirty-three".