Base | Representation |
---|---|
bin | 11101111011101110… |
… | …111101110011110001 |
3 | 10001221221100201212121 |
4 | 131323232331303301 |
5 | 1011311003233213 |
6 | 22433142154241 |
7 | 2215322163451 |
oct | 357356756361 |
9 | 101857321777 |
10 | 32140680433 |
11 | 126a3637a14 |
12 | 628ba22981 |
13 | 3052a27404 |
14 | 17ac883d61 |
15 | c81a2988d |
hex | 77bbbdcf1 |
32140680433 has 4 divisors (see below), whose sum is σ = 33177476608. Its totient is φ = 31103884260.
The previous prime is 32140680431. The next prime is 32140680469. The reversal of 32140680433 is 33408604123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33408604123 = 41 ⋅814844003.
It is a cyclic number.
It is not a de Polignac number, because 32140680433 - 21 = 32140680431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32140680431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518398041 + ... + 518398102.
It is an arithmetic number, because the mean of its divisors is an integer number (8294369152).
Almost surely, 232140680433 is an apocalyptic number.
It is an amenable number.
32140680433 is a deficient number, since it is larger than the sum of its proper divisors (1036796175).
32140680433 is a wasteful number, since it uses less digits than its factorization.
32140680433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1036796174.
The product of its (nonzero) digits is 41472, while the sum is 34.
The spelling of 32140680433 in words is "thirty-two billion, one hundred forty million, six hundred eighty thousand, four hundred thirty-three".
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