Base | Representation |
---|---|
bin | 1110100111011011101100… |
… | …01000011111100110010010 |
3 | 11012210200010001001101122211 |
4 | 13103231312020133212102 |
5 | 13203100210341322114 |
6 | 152205250150222334 |
7 | 6525061310041633 |
oct | 723556610374622 |
9 | 135720101041584 |
10 | 32141222214034 |
11 | a27201a02451a |
12 | 37312263549aa |
13 | 14c1b9a836b7b |
14 | 7d19018db88a |
15 | 3ab100e506c4 |
hex | 1d3b7621f992 |
32141222214034 has 4 divisors (see below), whose sum is σ = 48211833321054. Its totient is φ = 16070611107016.
The previous prime is 32141222214007. The next prime is 32141222214041. The reversal of 32141222214034 is 43041222214123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 32104655213409 + 36567000625 = 5666097^2 + 191225^2 .
It is a super-3 number, since 3×321412222140343 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32141222213987 and 32141222214005.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8035305553507 + ... + 8035305553510.
Almost surely, 232141222214034 is an apocalyptic number.
32141222214034 is a deficient number, since it is larger than the sum of its proper divisors (16070611107020).
32141222214034 is a wasteful number, since it uses less digits than its factorization.
32141222214034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16070611107019.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 32141222214034 its reverse (43041222214123), we get a palindrome (75182444428157).
The spelling of 32141222214034 in words is "thirty-two trillion, one hundred forty-one billion, two hundred twenty-two million, two hundred fourteen thousand, thirty-four".
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