32147113 has 4 divisors (see below), whose sum is σ = 32158720. Its totient is φ = 32135508.

The previous prime is 32147111. The next prime is 32147131. The reversal of 32147113 is 31174123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31174123 = 53 ⋅588191.

It is a cyclic number.

It is not a de Polignac number, because 32147113 - 2¹ = 32147111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32147111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1048 + ... + 8086.

It is an arithmetic number, because the mean of its divisors is an integer number (8039680).

Almost surely, 2^32147113 is an apocalyptic number.

It is an amenable number.

32147113 is a deficient number, since it is larger than the sum of its proper divisors (11607).

32147113 is an equidigital number, since it uses as much as digits as its factorization.

32147113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11606.

The product of its digits is 504, while the sum is 22.

The square root of 32147113 is about 5669.8424140359. The cubic root of 32147113 is about 317.9659820156.

The spelling of 32147113 in words is "thirty-two million, one hundred forty-seven thousand, one hundred thirteen".