Base | Representation |
---|---|
bin | 101110110010010011100… |
… | …011101011101010100111 |
3 | 102101100202121211111212111 |
4 | 232302103203223222213 |
5 | 410134021423021210 |
6 | 10501000205501451 |
7 | 451166310536611 |
oct | 56622343535247 |
9 | 12340677744774 |
10 | 3215111142055 |
11 | 102a58047062a |
12 | 43b13a271887 |
13 | 1a4250710247 |
14 | b187dc8ddb1 |
15 | 5897463388a |
hex | 2ec938ebaa7 |
3215111142055 has 4 divisors (see below), whose sum is σ = 3858133370472. Its totient is φ = 2572088913640.
The previous prime is 3215111141917. The next prime is 3215111142071. The reversal of 3215111142055 is 5502411115123.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-3215111142055 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321511114201 + ... + 321511114210.
It is an arithmetic number, because the mean of its divisors is an integer number (964533342618).
Almost surely, 23215111142055 is an apocalyptic number.
3215111142055 is a deficient number, since it is larger than the sum of its proper divisors (643022228417).
3215111142055 is an equidigital number, since it uses as much as digits as its factorization.
3215111142055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 643022228416.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 3215111142055 its reverse (5502411115123), we get a palindrome (8717522257178).
The spelling of 3215111142055 in words is "three trillion, two hundred fifteen billion, one hundred eleven million, one hundred forty-two thousand, fifty-five".
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