Base | Representation |
---|---|
bin | 1110101001001011010000… |
… | …10101010001000001010001 |
3 | 11020000101201102201112102221 |
4 | 13110211220111101001101 |
5 | 13210040343234121223 |
6 | 152252553532341041 |
7 | 6532311530523406 |
oct | 724455025210121 |
9 | 136011642645387 |
10 | 32201120223313 |
11 | a295466980428 |
12 | 3740962014781 |
13 | 14c7725104402 |
14 | 7d4784a022ad |
15 | 3ac959758b5d |
hex | 1d4968551051 |
32201120223313 has 4 divisors (see below), whose sum is σ = 33895916024560. Its totient is φ = 30506324422068.
The previous prime is 32201120223281. The next prime is 32201120223323. The reversal of 32201120223313 is 31332202110223.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 32201120223313 - 25 = 32201120223281 is a prime.
It is not an unprimeable number, because it can be changed into a prime (32201120223323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 847397900595 + ... + 847397900632.
It is an arithmetic number, because the mean of its divisors is an integer number (8473979006140).
Almost surely, 232201120223313 is an apocalyptic number.
It is an amenable number.
32201120223313 is a deficient number, since it is larger than the sum of its proper divisors (1694795801247).
32201120223313 is a wasteful number, since it uses less digits than its factorization.
32201120223313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1694795801246.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 32201120223313 its reverse (31332202110223), we get a palindrome (63533322333536).
The spelling of 32201120223313 in words is "thirty-two trillion, two hundred one billion, one hundred twenty million, two hundred twenty-three thousand, three hundred thirteen".
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