Base | Representation |
---|---|
bin | 1110101001001011010001… |
… | …11111010000101101110001 |
3 | 11020000101202012102211200021 |
4 | 13110211220333100231301 |
5 | 13210040404043411423 |
6 | 152252555004323441 |
7 | 6532312023224134 |
oct | 724455077205561 |
9 | 136011665384607 |
10 | 32201131232113 |
11 | a29547210a508 |
12 | 3740965843581 |
13 | 14c772748a1ac |
14 | 7d478626a21b |
15 | 3ac95a6d095d |
hex | 1d4968fd0b71 |
32201131232113 has 8 divisors (see below), whose sum is σ = 32291460407808. Its totient is φ = 32110891627584.
The previous prime is 32201131232099. The next prime is 32201131232191. The reversal of 32201131232113 is 31123213110223.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32201131232113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32201131230113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21672745 + ... + 23110822.
It is an arithmetic number, because the mean of its divisors is an integer number (4036432550976).
Almost surely, 232201131232113 is an apocalyptic number.
It is an amenable number.
32201131232113 is a deficient number, since it is larger than the sum of its proper divisors (90329175695).
32201131232113 is a wasteful number, since it uses less digits than its factorization.
32201131232113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44785583.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 32201131232113 its reverse (31123213110223), we get a palindrome (63324344342336).
The spelling of 32201131232113 in words is "thirty-two trillion, two hundred one billion, one hundred thirty-one million, two hundred thirty-two thousand, one hundred thirteen".
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