Base | Representation |
---|---|
bin | 101110110110111110010… |
… | …010111001110110110001 |
3 | 102101211200220202221121021 |
4 | 232312332102321312301 |
5 | 410224303010200223 |
6 | 10503145410055441 |
7 | 451434440000314 |
oct | 56667622716661 |
9 | 12354626687537 |
10 | 3220123131313 |
11 | 1031712617310 |
12 | 4400b887a581 |
13 | 1a486bba8c6a |
14 | b1bd779297b |
15 | 58b6965765d |
hex | 2edbe4b9db1 |
3220123131313 has 16 divisors (see below), whose sum is σ = 3534559991424. Its totient is φ = 2909309253760.
The previous prime is 3220123131301. The next prime is 3220123131319. The reversal of 3220123131313 is 3131313210223.
It is a cyclic number.
It is not a de Polignac number, because 3220123131313 - 233 = 3211533196721 is a prime.
It is a super-2 number, since 2×32201231313132 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3220123131319) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9789231 + ... + 10112827.
It is an arithmetic number, because the mean of its divisors is an integer number (220909999464).
Almost surely, 23220123131313 is an apocalyptic number.
It is an amenable number.
3220123131313 is a deficient number, since it is larger than the sum of its proper divisors (314436860111).
3220123131313 is a wasteful number, since it uses less digits than its factorization.
3220123131313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 329192.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3220123131313 its reverse (3131313210223), we get a palindrome (6351436341536).
The spelling of 3220123131313 in words is "three trillion, two hundred twenty billion, one hundred twenty-three million, one hundred thirty-one thousand, three hundred thirteen".
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