Base | Representation |
---|---|
bin | 101110110111001001100… |
… | …111100100111101100100 |
3 | 102101212012011020100211110 |
4 | 232313021213210331210 |
5 | 410230200123201012 |
6 | 10503220313505020 |
7 | 451442234465262 |
oct | 56671147447544 |
9 | 12355164210743 |
10 | 3220313100132 |
11 | 10317aa878737 |
12 | 440150412170 |
13 | 1a489c36044b |
14 | b1c14ac3432 |
15 | 58b7b17e73c |
hex | 2edc99e4f64 |
3220313100132 has 48 divisors (see below), whose sum is σ = 7617607300800. Its totient is φ = 1058648145408.
The previous prime is 3220313100089. The next prime is 3220313100133. The reversal of 3220313100132 is 2310013130223.
It is a junction number, because it is equal to n+sod(n) for n = 3220313100099 and 3220313100108.
It is not an unprimeable number, because it can be changed into a prime (3220313100133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11284744 + ... + 11566592.
It is an arithmetic number, because the mean of its divisors is an integer number (158700152100).
Almost surely, 23220313100132 is an apocalyptic number.
It is an amenable number.
3220313100132 is an abundant number, since it is smaller than the sum of its proper divisors (4397294200668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3220313100132 is a wasteful number, since it uses less digits than its factorization.
3220313100132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294972 (or 294970 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3220313100132 its reverse (2310013130223), we get a palindrome (5530326230355).
The spelling of 3220313100132 in words is "three trillion, two hundred twenty billion, three hundred thirteen million, one hundred thousand, one hundred thirty-two".
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