Base | Representation |
---|---|
bin | 101110111001101111110… |
… | …011011010100111010011 |
3 | 102102010101110120121002120 |
4 | 232321233303122213103 |
5 | 410301402403040311 |
6 | 10504401112545323 |
7 | 451601311230435 |
oct | 56715763324723 |
9 | 12363343517076 |
10 | 3223101221331 |
11 | 1032a00682432 |
12 | 4407aa0b2243 |
13 | 1a4c24b8b8c4 |
14 | b1ddb0d4655 |
15 | 58c90d1e706 |
hex | 2ee6fcda9d3 |
3223101221331 has 4 divisors (see below), whose sum is σ = 4297468295112. Its totient is φ = 2148734147552.
The previous prime is 3223101221321. The next prime is 3223101221387. The reversal of 3223101221331 is 1331221013223.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3223101221331 - 237 = 3085662267859 is a prime.
It is a super-3 number, since 3×32231012213313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (3223101221321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 537183536886 + ... + 537183536891.
It is an arithmetic number, because the mean of its divisors is an integer number (1074367073778).
Almost surely, 23223101221331 is an apocalyptic number.
3223101221331 is a deficient number, since it is larger than the sum of its proper divisors (1074367073781).
3223101221331 is a wasteful number, since it uses less digits than its factorization.
3223101221331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1074367073780.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 3223101221331 its reverse (1331221013223), we get a palindrome (4554322234554).
The spelling of 3223101221331 in words is "three trillion, two hundred twenty-three billion, one hundred one million, two hundred twenty-one thousand, three hundred thirty-one".
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