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3225220135077 = 31075073378359
BaseRepresentation
bin101110111011101110000…
…110011011100010100101
3102102022212010200120022110
4232323232012123202211
5410320222323310302
610505351244351233
7452004650550513
oct56735606334245
912368763616273
103225220135077
111033898759716
1244109b845519
131a51a1b6c615
14b215c6a54b3
1558d66d70b6c
hex2eeee19b8a5

3225220135077 has 4 divisors (see below), whose sum is σ = 4300293513440. Its totient is φ = 2150146756716.

The previous prime is 3225220135063. The next prime is 3225220135087. The reversal of 3225220135077 is 7705310225223.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3225220135077 - 26 = 3225220135013 is a prime.

It is a super-2 number, since 2×32252201350772 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3225220135037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 537536689177 + ... + 537536689182.

It is an arithmetic number, because the mean of its divisors is an integer number (1075073378360).

Almost surely, 23225220135077 is an apocalyptic number.

It is an amenable number.

3225220135077 is a deficient number, since it is larger than the sum of its proper divisors (1075073378363).

3225220135077 is a wasteful number, since it uses less digits than its factorization.

3225220135077 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1075073378362.

The product of its (nonzero) digits is 176400, while the sum is 39.

The spelling of 3225220135077 in words is "three trillion, two hundred twenty-five billion, two hundred twenty million, one hundred thirty-five thousand, seventy-seven".

Divisors: 1 3 1075073378359 3225220135077