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3225262495957 = 9833281040179
BaseRepresentation
bin101110111011110000101…
…000000001100011010101
3102102022222002101201111221
4232323300220001203111
5410320314144332312
610505355400330341
7452006003610565
oct56736050014325
912368862351457
103225262495957
11103390a662007
124410b1a739b1
131a51aa881928
14b2164170da5
1558d6a93c207
hex2eef0a018d5

3225262495957 has 4 divisors (see below), whose sum is σ = 3228543537120. Its totient is φ = 3221981454796.

The previous prime is 3225262495919. The next prime is 3225262495967. The reversal of 3225262495957 is 7595942625223.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3225262495957 - 223 = 3225254107349 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3225262495895 and 3225262495904.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3225262495907) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1640519107 + ... + 1640521072.

It is an arithmetic number, because the mean of its divisors is an integer number (807135884280).

Almost surely, 23225262495957 is an apocalyptic number.

It is an amenable number.

3225262495957 is a deficient number, since it is larger than the sum of its proper divisors (3281041163).

3225262495957 is an equidigital number, since it uses as much as digits as its factorization.

3225262495957 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3281041162.

The product of its digits is 81648000, while the sum is 61.

The spelling of 3225262495957 in words is "three trillion, two hundred twenty-five billion, two hundred sixty-two million, four hundred ninety-five thousand, nine hundred fifty-seven".

Divisors: 1 983 3281040179 3225262495957