Base | Representation |
---|---|
bin | 100100101110011000000111… |
… | …1011111010000101111000001 |
3 | 1120100202200111212222221121021 |
4 | 1021130300033133100233001 |
5 | 314320034240032320001 |
6 | 3103011245012225441 |
7 | 125020250210225110 |
oct | 11134601737205701 |
9 | 1510680455887537 |
10 | 323033340120001 |
11 | 93a23741043915 |
12 | 3029203800b281 |
13 | 10b32bb459c1b4 |
14 | 59aac7b855c77 |
15 | 2752c89ddcba1 |
hex | 125cc0f7d0bc1 |
323033340120001 has 4 divisors (see below), whose sum is σ = 369180960137152. Its totient is φ = 276885720102852.
The previous prime is 323033340119957. The next prime is 323033340120091. The reversal of 323033340120001 is 100021043330323.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 323033340120001 - 215 = 323033340087233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (323033340120091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23073810008565 + ... + 23073810008578.
It is an arithmetic number, because the mean of its divisors is an integer number (92295240034288).
Almost surely, 2323033340120001 is an apocalyptic number.
It is an amenable number.
323033340120001 is a deficient number, since it is larger than the sum of its proper divisors (46147620017151).
323033340120001 is an equidigital number, since it uses as much as digits as its factorization.
323033340120001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46147620017150.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 323033340120001 its reverse (100021043330323), we get a palindrome (423054383450324).
The spelling of 323033340120001 in words is "three hundred twenty-three trillion, thirty-three billion, three hundred forty million, one hundred twenty thousand, one".
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