Base | Representation |
---|---|
bin | 101111000001011001101… |
… | …100011100100011100001 |
3 | 102102220121021002111120020 |
4 | 233001121230130203201 |
5 | 410420220434330423 |
6 | 10512240434504053 |
7 | 452312061525243 |
oct | 57013154344341 |
9 | 12386537074506 |
10 | 3231320230113 |
11 | 1036439036378 |
12 | 442302735029 |
13 | 1a59348b3201 |
14 | b257a8cc093 |
15 | 590c267b4e3 |
hex | 2f059b1c8e1 |
3231320230113 has 8 divisors (see below), whose sum is σ = 4308507940128. Its totient is φ = 2154173003424.
The previous prime is 3231320230111. The next prime is 3231320230121. The reversal of 3231320230113 is 3110320231323.
3231320230113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3231320230113 - 21 = 3231320230111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3231320230111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9934095 + ... + 10254212.
It is an arithmetic number, because the mean of its divisors is an integer number (538563492516).
Almost surely, 23231320230113 is an apocalyptic number.
It is an amenable number.
3231320230113 is a deficient number, since it is larger than the sum of its proper divisors (1077187710015).
3231320230113 is a wasteful number, since it uses less digits than its factorization.
3231320230113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20241663.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 3231320230113 its reverse (3110320231323), we get a palindrome (6341640461436).
The spelling of 3231320230113 in words is "three trillion, two hundred thirty-one billion, three hundred twenty million, two hundred thirty thousand, one hundred thirteen".
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