Base | Representation |
---|---|
bin | 101111001001100001011… |
… | …100010001100100001010 |
3 | 102110202002222010222110000 |
4 | 233021201130101210022 |
5 | 411041100234034424 |
6 | 10520242012503430 |
7 | 453041133544155 |
oct | 57114134214412 |
9 | 12422088128400 |
10 | 3240040143114 |
11 | 103a103214045 |
12 | 443b36a7ab76 |
13 | 1a66c4318348 |
14 | b2b66a34c9c |
15 | 59432e7e3c9 |
hex | 2f26171190a |
3240040143114 has 20 divisors (see below), whose sum is σ = 7260089950674. Its totient is φ = 1080013380984.
The previous prime is 3240040143091. The next prime is 3240040143121. The reversal of 3240040143114 is 4113410400423.
3240040143114 is a `hidden beast` number, since 3 + 2 + 400 + 4 + 0 + 143 + 114 = 666.
It can be written as a sum of positive squares in only one way, i.e., 3178315225089 + 61724918025 = 1782783^2 + 248445^2 .
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 10000123737 + ... + 10000124060.
Almost surely, 23240040143114 is an apocalyptic number.
3240040143114 is an abundant number, since it is smaller than the sum of its proper divisors (4020049807560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3240040143114 is a wasteful number, since it uses less digits than its factorization.
3240040143114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20000247811 (or 20000247802 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 3240040143114 its reverse (4113410400423), we get a palindrome (7353450543537).
The spelling of 3240040143114 in words is "three trillion, two hundred forty billion, forty million, one hundred forty-three thousand, one hundred fourteen".
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