Base | Representation |
---|---|
bin | 101111001010011010101… |
… | …001110101111110001111 |
3 | 102110211120212021211111202 |
4 | 233022122221311332033 |
5 | 411100032000021143 |
6 | 10520521141540115 |
7 | 453104000316662 |
oct | 57123251657617 |
9 | 12424525254452 |
10 | 3241000001423 |
11 | 103a55600a878 |
12 | 44416441463b |
13 | 1a681813c342 |
14 | b2c182d36d9 |
15 | 5948c381ab8 |
hex | 2f29aa75f8f |
3241000001423 has 4 divisors (see below), whose sum is σ = 3246040437528. Its totient is φ = 3235959565320.
The previous prime is 3241000001381. The next prime is 3241000001441.
3241000001423 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3241000001423 - 26 = 3241000001359 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3241000001395 and 3241000001404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3241000001923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2520217088 + ... + 2520218373.
It is an arithmetic number, because the mean of its divisors is an integer number (811510109382).
Almost surely, 23241000001423 is an apocalyptic number.
3241000001423 is a deficient number, since it is larger than the sum of its proper divisors (5040436105).
3241000001423 is an equidigital number, since it uses as much as digits as its factorization.
3241000001423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5040436104.
The product of its (nonzero) digits is 576, while the sum is 20.
It can be divided in two parts, 324100000 and 1423, that added together give a palindrome (324101423).
The spelling of 3241000001423 in words is "three trillion, two hundred forty-one billion, one thousand, four hundred twenty-three".
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