Base | Representation |
---|---|
bin | 101111001100011010010… |
… | …101000100111011100011 |
3 | 102111001010010220201211120 |
4 | 233030122111010323203 |
5 | 411113423330310230 |
6 | 10521513501143323 |
7 | 453211040336151 |
oct | 57143225047343 |
9 | 12431103821746 |
10 | 3243142041315 |
11 | 1040455152080 |
12 | 44466185ab43 |
13 | 1a6a99b59377 |
14 | b2d7c9a43d1 |
15 | 59565450310 |
hex | 2f31a544ee3 |
3243142041315 has 128 divisors (see below), whose sum is σ = 6010935091200. Its totient is φ = 1476669680640.
The previous prime is 3243142041287. The next prime is 3243142041317. The reversal of 3243142041315 is 5131402413423.
It is not a de Polignac number, because 3243142041315 - 25 = 3243142041283 is a prime.
It is a super-3 number, since 3×32431420413153 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (3243142041317) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 165803506 + ... + 165823064.
It is an arithmetic number, because the mean of its divisors is an integer number (46960430400).
Almost surely, 23243142041315 is an apocalyptic number.
3243142041315 is a deficient number, since it is larger than the sum of its proper divisors (2767793049885).
3243142041315 is a wasteful number, since it uses less digits than its factorization.
3243142041315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20057.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 3243142041315 its reverse (5131402413423), we get a palindrome (8374544454738).
The spelling of 3243142041315 in words is "three trillion, two hundred forty-three billion, one hundred forty-two million, forty-one thousand, three hundred fifteen".
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