Base | Representation |
---|---|
bin | 101111001100100011110… |
… | …011011110100011100101 |
3 | 102111001112020000221202111 |
4 | 233030203303132203211 |
5 | 411114240024134131 |
6 | 10521541340241021 |
7 | 453215010452542 |
oct | 57144363364345 |
9 | 12431466027674 |
10 | 3243301005541 |
11 | 1040526957273 |
12 | 4446a6b40171 |
13 | 1a6ac3a7653c |
14 | b2d95b43bc9 |
15 | 595743a0ab1 |
hex | 2f323cde8e5 |
3243301005541 has 4 divisors (see below), whose sum is σ = 3254843002284. Its totient is φ = 3231759008800.
The previous prime is 3243301005517. The next prime is 3243301005559. The reversal of 3243301005541 is 1455001033423.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 899557402500 + 2343743603041 = 948450^2 + 1530929^2 .
It is a cyclic number.
It is not a de Polignac number, because 3243301005541 - 25 = 3243301005509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3243301006541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5770997950 + ... + 5770998511.
It is an arithmetic number, because the mean of its divisors is an integer number (813710750571).
Almost surely, 23243301005541 is an apocalyptic number.
It is an amenable number.
3243301005541 is a deficient number, since it is larger than the sum of its proper divisors (11541996743).
3243301005541 is a wasteful number, since it uses less digits than its factorization.
3243301005541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11541996742.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 3243301005541 its reverse (1455001033423), we get a palindrome (4698302038964).
The spelling of 3243301005541 in words is "three trillion, two hundred forty-three billion, three hundred one million, five thousand, five hundred forty-one".
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