Base | Representation |
---|---|
bin | 11110001101001111… |
… | …001101000001001101 |
3 | 10002201101221101120111 |
4 | 132031033031001031 |
5 | 1012411143002023 |
6 | 22522232320021 |
7 | 2225516242501 |
oct | 361517150115 |
9 | 102641841514 |
10 | 32434344013 |
11 | 12834383795 |
12 | 6352243011 |
13 | 309b817046 |
14 | 17d9888301 |
15 | c9c6d600d |
hex | 78d3cd04d |
32434344013 has 4 divisors (see below), whose sum is σ = 34342246620. Its totient is φ = 30526441408.
The previous prime is 32434344011. The next prime is 32434344023. The reversal of 32434344013 is 31044343423.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 18923303844 + 13511040169 = 137562^2 + 116237^2 .
It is not a de Polignac number, because 32434344013 - 21 = 32434344011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32434344011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 953951278 + ... + 953951311.
It is an arithmetic number, because the mean of its divisors is an integer number (8585561655).
Almost surely, 232434344013 is an apocalyptic number.
It is an amenable number.
32434344013 is a deficient number, since it is larger than the sum of its proper divisors (1907902607).
32434344013 is a wasteful number, since it uses less digits than its factorization.
32434344013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1907902606.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 32434344013 its reverse (31044343423), we get a palindrome (63478687436).
The spelling of 32434344013 in words is "thirty-two billion, four hundred thirty-four million, three hundred forty-four thousand, thirteen".
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