32444144342413 has 4 divisors (see below), whose sum is σ = 32444156341728. Its totient is φ = 32444132343100.

The previous prime is 32444144342381. The next prime is 32444144342443. The reversal of 32444144342413 is 31424344144423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 32444144342413 - 2⁵ = 32444144342381 is a prime.

It is a super-2 number, since 2×32444144342413² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 32444144342413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32444144342443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172920 + ... + 8057182.

It is an arithmetic number, because the mean of its divisors is an integer number (8111039085432).

Almost surely, 2^{32444144342413} is an apocalyptic number.

It is an amenable number.

32444144342413 is a deficient number, since it is larger than the sum of its proper divisors (11999315).

32444144342413 is an equidigital number, since it uses as much as digits as its factorization.

32444144342413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11999314.

The product of its digits is 1769472, while the sum is 43.

Adding to 32444144342413 its reverse (31424344144423), we get a palindrome (63868488486836).

The spelling of 32444144342413 in words is "thirty-two trillion, four hundred forty-four billion, one hundred forty-four million, three hundred forty-two thousand, four hundred thirteen".