Base | Representation |
---|---|
bin | 101111010010110010100… |
… | …011110001110101111111 |
3 | 102111200210110102212002200 |
4 | 233102302203301311333 |
5 | 411221440143440143 |
6 | 10525005242122543 |
7 | 453542543456100 |
oct | 57226243616577 |
9 | 12450713385080 |
10 | 3249990999423 |
11 | 104334a212733 |
12 | 445a534b0453 |
13 | 1a761ba8a0bc |
14 | b342c4443a7 |
15 | 598168811d3 |
hex | 2f4b28f1d7f |
3249990999423 has 36 divisors (see below), whose sum is σ = 5608460318760. Its totient is φ = 1806944793696.
The previous prime is 3249990999421. The next prime is 3249990999457.
3249990999423 is a `hidden beast` number, since 3 + 2 + 499 + 9 + 0 + 9 + 99 + 42 + 3 = 666.
3249990999423 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3249990999423 - 21 = 3249990999421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3249990999421) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 99572793 + ... + 99605426.
It is an arithmetic number, because the mean of its divisors is an integer number (155790564410).
Almost surely, 23249990999423 is an apocalyptic number.
3249990999423 is a deficient number, since it is larger than the sum of its proper divisors (2358469319337).
3249990999423 is a wasteful number, since it uses less digits than its factorization.
3249990999423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 199178276 (or 199178266 counting only the distinct ones).
The product of its (nonzero) digits is 306110016, while the sum is 72.
The spelling of 3249990999423 in words is "three trillion, two hundred forty-nine billion, nine hundred ninety million, nine hundred ninety-nine thousand, four hundred twenty-three".
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