Base | Representation |
---|---|
bin | 100100111100110001000110… |
… | …1001010010000111001110010 |
3 | 1120121202202112201011200011111 |
4 | 1021321202031022100321302 |
5 | 320044440300134013132 |
6 | 3111124015320303534 |
7 | 125313164604461632 |
oct | 11171421512207162 |
9 | 1517682481150144 |
10 | 325011133501042 |
11 | 946164a192514a |
12 | 30551403011baa |
13 | 10c4755924a641 |
14 | 5a388a0d3c6c2 |
15 | 2789443576647 |
hex | 127988d290e72 |
325011133501042 has 16 divisors (see below), whose sum is σ = 489624138480672. Its totient is φ = 161803130338080.
The previous prime is 325011133501039. The next prime is 325011133501051. The reversal of 325011133501042 is 240105331110523.
It is a junction number, because it is equal to n+sod(n) for n = 325011133500995 and 325011133501013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4407853 + ... + 25873759.
It is an arithmetic number, because the mean of its divisors is an integer number (30601508655042).
Almost surely, 2325011133501042 is an apocalyptic number.
325011133501042 is a deficient number, since it is larger than the sum of its proper divisors (164613004979630).
325011133501042 is a wasteful number, since it uses less digits than its factorization.
325011133501042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21498633.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 325011133501042 its reverse (240105331110523), we get a palindrome (565116464611565).
The spelling of 325011133501042 in words is "three hundred twenty-five trillion, eleven billion, one hundred thirty-three million, five hundred one thousand, forty-two".
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