325120655100253 has 4 divisors (see below), whose sum is σ = 325123009359840. Its totient is φ = 325118300840668.

The previous prime is 325120655100223. The next prime is 325120655100313. The reversal of 325120655100253 is 352001556021523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-325120655100253 is a prime.

It is a super-3 number, since 3×325120655100253³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325120655100223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1176922633 + ... + 1177198846.

It is an arithmetic number, because the mean of its divisors is an integer number (81280752339960).

Almost surely, 2^{325120655100253} is an apocalyptic number.

It is an amenable number.

325120655100253 is a deficient number, since it is larger than the sum of its proper divisors (2354259587).

325120655100253 is a wasteful number, since it uses less digits than its factorization.

325120655100253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2354259586.

The product of its (nonzero) digits is 270000, while the sum is 40.

The spelling of 325120655100253 in words is "three hundred twenty-five trillion, one hundred twenty billion, six hundred fifty-five million, one hundred thousand, two hundred fifty-three".