Base | Representation |
---|---|
bin | 101111010100000110110… |
… | …111010100111100000111 |
3 | 102111211110000220100201122 |
4 | 233110012313110330013 |
5 | 411232334241110210 |
6 | 10525401445544155 |
7 | 453622566661205 |
oct | 57240667247407 |
9 | 12454400810648 |
10 | 3251405410055 |
11 | 1043a05654340 |
12 | 44618911505b |
13 | 1a77b5b12b7a |
14 | b3524228075 |
15 | 5989ab20b55 |
hex | 2f506dd4f07 |
3251405410055 has 16 divisors (see below), whose sum is σ = 4257113148288. Its totient is φ = 2364254100000.
The previous prime is 3251405410049. The next prime is 3251405410061. The reversal of 3251405410055 is 5500145041523.
It is an interprime number because it is at equal distance from previous prime (3251405410049) and next prime (3251405410061).
It is not a de Polignac number, because 3251405410055 - 224 = 3251388632839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3251405409997 and 3251405410024.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4730021 + ... + 5373630.
It is an arithmetic number, because the mean of its divisors is an integer number (266069571768).
Almost surely, 23251405410055 is an apocalyptic number.
3251405410055 is a deficient number, since it is larger than the sum of its proper divisors (1005707738233).
3251405410055 is a wasteful number, since it uses less digits than its factorization.
3251405410055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10109518.
The product of its (nonzero) digits is 60000, while the sum is 35.
The spelling of 3251405410055 in words is "three trillion, two hundred fifty-one billion, four hundred five million, four hundred ten thousand, fifty-five".
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