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325140999 = 3433250301
BaseRepresentation
bin10011011000010…
…100001000000111
3211122210212121020
4103120110020013
51131214002444
652132522223
711025436641
oct2330241007
9748725536
10325140999
11157596277
1290a80373
1352491231
1431279891
151d828119
hex13614207

325140999 has 8 divisors (see below), whose sum is σ = 434524272. Its totient is φ = 216259200.

The previous prime is 325140983. The next prime is 325141009. The reversal of 325140999 is 999041523.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 325140999 - 24 = 325140983 is a prime.

It is a super-3 number, since 3×3251409993 (a number of 27 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 325140999.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325140899) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123852 + ... + 126449.

It is an arithmetic number, because the mean of its divisors is an integer number (54315534).

Almost surely, 2325140999 is an apocalyptic number.

325140999 is a deficient number, since it is larger than the sum of its proper divisors (109383273).

325140999 is a wasteful number, since it uses less digits than its factorization.

325140999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 250737.

The product of its (nonzero) digits is 87480, while the sum is 42.

The square root of 325140999 is about 18031.6665619127. Note that the first 3 decimals coincide. The cubic root of 325140999 is about 687.6338465133.

The spelling of 325140999 in words is "three hundred twenty-five million, one hundred forty thousand, nine hundred ninety-nine".

Divisors: 1 3 433 1299 250301 750903 108380333 325140999