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3252255151143 = 31084085050381
BaseRepresentation
bin101111010100111001100…
…000110101010000100111
3102111220122020211200100210
4233110321200311100213
5411241104304314033
610530022042510503
7453652625443365
oct57247140652047
912456566750323
103252255151143
1110443012793a9
12446385805433
131a78bcb9034b
14b35a5020635
15598ea520d63
hex2f539835427

3252255151143 has 4 divisors (see below), whose sum is σ = 4336340201528. Its totient is φ = 2168170100760.

The previous prime is 3252255151127. The next prime is 3252255151253. The reversal of 3252255151143 is 3411515522523.

3252255151143 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 3252255151143 - 24 = 3252255151127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3252255131143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542042525188 + ... + 542042525193.

It is an arithmetic number, because the mean of its divisors is an integer number (1084085050382).

Almost surely, 23252255151143 is an apocalyptic number.

3252255151143 is a deficient number, since it is larger than the sum of its proper divisors (1084085050385).

3252255151143 is a wasteful number, since it uses less digits than its factorization.

3252255151143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1084085050384.

The product of its digits is 180000, while the sum is 39.

The spelling of 3252255151143 in words is "three trillion, two hundred fifty-two billion, two hundred fifty-five million, one hundred fifty-one thousand, one hundred forty-three".

Divisors: 1 3 1084085050381 3252255151143