325400051 has 4 divisors (see below), whose sum is σ = 325438704. Its totient is φ = 325361400.

The previous prime is 325400027. The next prime is 325400063. The reversal of 325400051 is 150004523.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 150004523 = 5009 ⋅29947.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-325400051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 325399996 and 325400032.

It is not an unprimeable number, because it can be changed into a prime (325400081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 740 + ... + 25521.

It is an arithmetic number, because the mean of its divisors is an integer number (81359676).

Almost surely, 2^325400051 is an apocalyptic number.

325400051 is a deficient number, since it is larger than the sum of its proper divisors (38653).

325400051 is a wasteful number, since it uses less digits than its factorization.

325400051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38652.

The product of its (nonzero) digits is 600, while the sum is 20.

The square root of 325400051 is about 18038.8483834196. The cubic root of 325400051 is about 687.8164192395.

Adding to 325400051 its reverse (150004523), we get a palindrome (475404574).

The spelling of 325400051 in words is "three hundred twenty-five million, four hundred thousand, fifty-one".