Base | Representation |
---|---|
bin | 1110110011000010101010… |
… | …00110101101000100010011 |
3 | 11021012210200112002012021121 |
4 | 13121201111012231010103 |
5 | 13231114111103232230 |
6 | 153112414322503111 |
7 | 6565642004540116 |
oct | 731412506550423 |
9 | 137183615065247 |
10 | 32540100055315 |
11 | a4061a7187416 |
12 | 37965a5804a97 |
13 | 1520697836668 |
14 | 806d40a3457d |
15 | 3b669908777a |
hex | 1d98551ad113 |
32540100055315 has 8 divisors (see below), whose sum is σ = 39082045459968. Its totient is φ = 26009463115200.
The previous prime is 32540100055313. The next prime is 32540100055349. The reversal of 32540100055315 is 51355000104523.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 32540100055315 - 21 = 32540100055313 is a prime.
It is a super-2 number, since 2×325401000553152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32540100055313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2827109802 + ... + 2827121311.
It is an arithmetic number, because the mean of its divisors is an integer number (4885255682496).
Almost surely, 232540100055315 is an apocalyptic number.
32540100055315 is a deficient number, since it is larger than the sum of its proper divisors (6541945404653).
32540100055315 is a wasteful number, since it uses less digits than its factorization.
32540100055315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5654232269.
The product of its (nonzero) digits is 45000, while the sum is 34.
Adding to 32540100055315 its reverse (51355000104523), we get a palindrome (83895100159838).
The spelling of 32540100055315 in words is "thirty-two trillion, five hundred forty billion, one hundred million, fifty-five thousand, three hundred fifteen".
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