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3254073145 = 5650814629
BaseRepresentation
bin1100000111110101…
…0011011100111001
322101210010001011121
43001331103130321
523131020320040
61254522025241
7143432110501
oct30175233471
98353101147
103254073145
11141a926354
12769948221
133cb221b8b
1422c262a01
15140a2ec4a
hexc1f53739

3254073145 has 4 divisors (see below), whose sum is σ = 3904887780. Its totient is φ = 2603258512.

The previous prime is 3254073127. The next prime is 3254073149. The reversal of 3254073145 is 5413704523.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1121111289 + 2132961856 = 33483^2 + 46184^2 .

It is a cyclic number.

It is not a de Polignac number, because 3254073145 - 25 = 3254073113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3254073145.

It is not an unprimeable number, because it can be changed into a prime (3254073149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325407310 + ... + 325407319.

It is an arithmetic number, because the mean of its divisors is an integer number (976221945).

Almost surely, 23254073145 is an apocalyptic number.

It is an amenable number.

3254073145 is a deficient number, since it is larger than the sum of its proper divisors (650814635).

3254073145 is an equidigital number, since it uses as much as digits as its factorization.

3254073145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 650814634.

The product of its (nonzero) digits is 50400, while the sum is 34.

The square root of 3254073145 is about 57044.4839138720. The cubic root of 3254073145 is about 1481.8665797729.

Adding to 3254073145 its reverse (5413704523), we get a palindrome (8667777668).

The spelling of 3254073145 in words is "three billion, two hundred fifty-four million, seventy-three thousand, one hundred forty-five".

Divisors: 1 5 650814629 3254073145