Base | Representation |
---|---|
bin | 1110110011001011111111… |
… | …11111000000001011001101 |
3 | 11021020021121222111111222210 |
4 | 13121211333333000023031 |
5 | 13231204343243032023 |
6 | 153115004050101033 |
7 | 6566210163140622 |
oct | 731457777001315 |
9 | 137207558444883 |
10 | 32545114424013 |
11 | a40833a708884 |
12 | 3797564b7a779 |
13 | 1520cb6656429 |
14 | 807298996349 |
15 | 3b688e3cb593 |
hex | 1d997ffc02cd |
32545114424013 has 8 divisors (see below), whose sum is σ = 43394060743488. Its totient is φ = 21696455526944.
The previous prime is 32545114423999. The next prime is 32545114424023. The reversal of 32545114424013 is 31042441154523.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 32545114424013 - 25 = 32545114423981 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32545114424023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71591256 + ... + 72044417.
It is an arithmetic number, because the mean of its divisors is an integer number (5424257592936).
Almost surely, 232545114424013 is an apocalyptic number.
It is an amenable number.
32545114424013 is a deficient number, since it is larger than the sum of its proper divisors (10848946319475).
32545114424013 is a wasteful number, since it uses less digits than its factorization.
32545114424013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143711203.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 32545114424013 its reverse (31042441154523), we get a palindrome (63587555578536).
The spelling of 32545114424013 in words is "thirty-two trillion, five hundred forty-five billion, one hundred fourteen million, four hundred twenty-four thousand, thirteen".
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