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32550025141 = 311050000811
BaseRepresentation
bin11110010100001000…
…011111011110110101
310010000110121121020201
4132110020133132311
51013130301301031
622541524000501
72231422435324
oct362410373665
9103013547221
1032550025141
1112893705727
126384b30131
1330b978b20a
14180ad9c0bb
15ca7936d61
hex79421f7b5

32550025141 has 4 divisors (see below), whose sum is σ = 33600025984. Its totient is φ = 31500024300.

The previous prime is 32550025127. The next prime is 32550025153. The reversal of 32550025141 is 14152005523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14152005523 = 68832056081.

It is a cyclic number.

It is not a de Polignac number, because 32550025141 - 219 = 32549500853 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (32550025121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 525000375 + ... + 525000436.

It is an arithmetic number, because the mean of its divisors is an integer number (8400006496).

Almost surely, 232550025141 is an apocalyptic number.

32550025141 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

32550025141 is a deficient number, since it is larger than the sum of its proper divisors (1050000843).

32550025141 is a wasteful number, since it uses less digits than its factorization.

32550025141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1050000842.

The product of its (nonzero) digits is 6000, while the sum is 28.

The spelling of 32550025141 in words is "thirty-two billion, five hundred fifty million, twenty-five thousand, one hundred forty-one".

Divisors: 1 31 1050000811 32550025141