Base | Representation |
---|---|
bin | 1110110011010111000000… |
… | …00011010101100010110111 |
3 | 11021020211212122000210021011 |
4 | 13121223200003111202313 |
5 | 13231303442402441101 |
6 | 153121422131333051 |
7 | 6566506435325443 |
oct | 731534003254267 |
9 | 137224778023234 |
10 | 32551021140151 |
11 | a40a8a0915068 |
12 | 3798733151187 |
13 | 15217182c0637 |
14 | 807699241823 |
15 | 3b6ad7c39751 |
hex | 1d9ae00d58b7 |
32551021140151 has 4 divisors (see below), whose sum is σ = 33009486226704. Its totient is φ = 32092556053600.
The previous prime is 32551021140137. The next prime is 32551021140161. The reversal of 32551021140151 is 15104112015523.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 32551021140151 - 27 = 32551021140023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32551021140161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229232543170 + ... + 229232543311.
It is an arithmetic number, because the mean of its divisors is an integer number (8252371556676).
Almost surely, 232551021140151 is an apocalyptic number.
32551021140151 is a deficient number, since it is larger than the sum of its proper divisors (458465086553).
32551021140151 is an equidigital number, since it uses as much as digits as its factorization.
32551021140151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 458465086552.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 32551021140151 its reverse (15104112015523), we get a palindrome (47655133155674).
The spelling of 32551021140151 in words is "thirty-two trillion, five hundred fifty-one billion, twenty-one million, one hundred forty thousand, one hundred fifty-one".
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