Base | Representation |
---|---|
bin | 101111011100011110111… |
… | …001101101110101000111 |
3 | 102112200122210012222010020 |
4 | 233130132321231311013 |
5 | 411404244021432241 |
6 | 10533450105430223 |
7 | 454361501020101 |
oct | 57343671556507 |
9 | 12480583188106 |
10 | 3260398624071 |
11 | 1047800030116 |
12 | 447a78a9b373 |
13 | 1a85ba058494 |
14 | b3b38794571 |
15 | 59c2540bb66 |
hex | 2f71ee6dd47 |
3260398624071 has 4 divisors (see below), whose sum is σ = 4347198165432. Its totient is φ = 2173599082712.
The previous prime is 3260398624057. The next prime is 3260398624081. The reversal of 3260398624071 is 1704268930623.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3260398624071 - 213 = 3260398615879 is a prime.
It is a super-2 number, since 2×32603986240712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3260398624081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 543399770676 + ... + 543399770681.
It is an arithmetic number, because the mean of its divisors is an integer number (1086799541358).
Almost surely, 23260398624071 is an apocalyptic number.
3260398624071 is a deficient number, since it is larger than the sum of its proper divisors (1086799541361).
3260398624071 is a wasteful number, since it uses less digits than its factorization.
3260398624071 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1086799541360.
The product of its (nonzero) digits is 2612736, while the sum is 51.
The spelling of 3260398624071 in words is "three trillion, two hundred sixty billion, three hundred ninety-eight million, six hundred twenty-four thousand, seventy-one".
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