Base | Representation |
---|---|
bin | 110000000000011110001… |
… | …000101110111010011001 |
3 | 102200101101210201002200222 |
4 | 300000132020232322121 |
5 | 413022413331122423 |
6 | 11003320331005425 |
7 | 460230204321545 |
oct | 60003610567231 |
9 | 12611353632628 |
10 | 3299040489113 |
11 | 106212a394276 |
12 | 453461b99875 |
13 | 1ac137929995 |
14 | b596282aa25 |
15 | 5ac37a6d3c8 |
hex | 3001e22ee99 |
3299040489113 has 4 divisors (see below), whose sum is σ = 3309447557220. Its totient is φ = 3288633421008.
The previous prime is 3299040489083. The next prime is 3299040489139. The reversal of 3299040489113 is 3119840409923.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 200747010304 + 3098293478809 = 448048^2 + 1760197^2 .
It is a cyclic number.
It is not a de Polignac number, because 3299040489113 - 26 = 3299040489049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3299040489013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5203533578 + ... + 5203534211.
It is an arithmetic number, because the mean of its divisors is an integer number (827361889305).
Almost surely, 23299040489113 is an apocalyptic number.
It is an amenable number.
3299040489113 is a deficient number, since it is larger than the sum of its proper divisors (10407068107).
3299040489113 is a wasteful number, since it uses less digits than its factorization.
3299040489113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10407068106.
The product of its (nonzero) digits is 1679616, while the sum is 53.
The spelling of 3299040489113 in words is "three trillion, two hundred ninety-nine billion, forty million, four hundred eighty-nine thousand, one hundred thirteen".
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