Base | Representation |
---|---|
bin | 1111000000011011100001… |
… | …01100010101000101000010 |
3 | 11022211210002102001102012001 |
4 | 13200031300230111011002 |
5 | 13311133223321412114 |
6 | 154104014201054214 |
7 | 6644115563146264 |
oct | 740156054250502 |
9 | 138753072042161 |
10 | 33000124404034 |
11 | a573301a07387 |
12 | 384b78aa8736a |
13 | 1554b8a9787b8 |
14 | 8213009c7b34 |
15 | 3c36203e3374 |
hex | 1e0370b15142 |
33000124404034 has 4 divisors (see below), whose sum is σ = 49500186606054. Its totient is φ = 16500062202016.
The previous prime is 33000124404001. The next prime is 33000124404047. The reversal of 33000124404034 is 43040442100033.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 32999314717009 + 809687025 = 5744503^2 + 28455^2 .
It is a super-3 number, since 3×330001244040343 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33000124403993 and 33000124404011.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8250031101007 + ... + 8250031101010.
Almost surely, 233000124404034 is an apocalyptic number.
33000124404034 is a deficient number, since it is larger than the sum of its proper divisors (16500062202020).
33000124404034 is a wasteful number, since it uses less digits than its factorization.
33000124404034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16500062202019.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 33000124404034 its reverse (43040442100033), we get a palindrome (76040566504067).
The spelling of 33000124404034 in words is "thirty-three trillion, one hundred twenty-four million, four hundred four thousand, thirty-four".
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