Base | Representation |
---|---|
bin | 1111000000110010000100… |
… | …11111010001111111000001 |
3 | 11022212221100100122101222121 |
4 | 13200121002133101333001 |
5 | 13311333023414232231 |
6 | 154113335550404241 |
7 | 6645024636146653 |
oct | 740310237217701 |
9 | 138787310571877 |
10 | 33012234133441 |
11 | a5784565a5312 |
12 | 3851baa500681 |
13 | 155606a77c464 |
14 | 821b2d00a6d3 |
15 | 3c3acd5db311 |
hex | 1e06427d1fc1 |
33012234133441 has 4 divisors (see below), whose sum is σ = 33012280131012. Its totient is φ = 33012188135872.
The previous prime is 33012234133421. The next prime is 33012234133457. The reversal of 33012234133441 is 14433143221033.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 15453586521025 + 17558647612416 = 3931105^2 + 4190304^2 .
It is a cyclic number.
It is not a de Polignac number, because 33012234133441 - 29 = 33012234132929 is a prime.
It is a super-2 number, since 2×330122341334412 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 33012234133397 and 33012234133406.
It is not an unprimeable number, because it can be changed into a prime (33012234133421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21904900 + ... + 23363413.
It is an arithmetic number, because the mean of its divisors is an integer number (8253070032753).
Almost surely, 233012234133441 is an apocalyptic number.
It is an amenable number.
33012234133441 is a deficient number, since it is larger than the sum of its proper divisors (45997571).
33012234133441 is an equidigital number, since it uses as much as digits as its factorization.
33012234133441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45997570.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 33012234133441 its reverse (14433143221033), we get a palindrome (47445377354474).
The spelling of 33012234133441 in words is "thirty-three trillion, twelve billion, two hundred thirty-four million, one hundred thirty-three thousand, four hundred forty-one".
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