Base | Representation |
---|---|
bin | 1111000000110101010111… |
… | …11000011101000100010001 |
3 | 11022220002220120211121112121 |
4 | 13200122223320131010101 |
5 | 13311400134044340423 |
6 | 154114231233254241 |
7 | 6645116516516314 |
oct | 740325370350421 |
9 | 138802816747477 |
10 | 33014002340113 |
11 | a579183714143 |
12 | 3852402704381 |
13 | 155628cbba1b2 |
14 | 821c59ba897b |
15 | 3c3b8396445d |
hex | 1e06abe1d111 |
33014002340113 has 8 divisors (see below), whose sum is σ = 35254107060480. Its totient is φ = 30847343676240.
The previous prime is 33014002340107. The next prime is 33014002340149. The reversal of 33014002340113 is 31104320041033.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 33014002340113 - 29 = 33014002339601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33014002340213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18361513195 + ... + 18361514992.
It is an arithmetic number, because the mean of its divisors is an integer number (4406763382560).
Almost surely, 233014002340113 is an apocalyptic number.
It is an amenable number.
33014002340113 is a deficient number, since it is larger than the sum of its proper divisors (2240104720367).
33014002340113 is a wasteful number, since it uses less digits than its factorization.
33014002340113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36723028247.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 33014002340113 its reverse (31104320041033), we get a palindrome (64118322381146).
The spelling of 33014002340113 in words is "thirty-three trillion, fourteen billion, two million, three hundred forty thousand, one hundred thirteen".
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