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33014002340113 = 293136723028187
BaseRepresentation
bin1111000000110101010111…
…11000011101000100010001
311022220002220120211121112121
413200122223320131010101
513311400134044340423
6154114231233254241
76645116516516314
oct740325370350421
9138802816747477
1033014002340113
11a579183714143
123852402704381
13155628cbba1b2
14821c59ba897b
153c3b8396445d
hex1e06abe1d111

33014002340113 has 8 divisors (see below), whose sum is σ = 35254107060480. Its totient is φ = 30847343676240.

The previous prime is 33014002340107. The next prime is 33014002340149. The reversal of 33014002340113 is 31104320041033.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 33014002340113 - 29 = 33014002339601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33014002340213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18361513195 + ... + 18361514992.

It is an arithmetic number, because the mean of its divisors is an integer number (4406763382560).

Almost surely, 233014002340113 is an apocalyptic number.

It is an amenable number.

33014002340113 is a deficient number, since it is larger than the sum of its proper divisors (2240104720367).

33014002340113 is a wasteful number, since it uses less digits than its factorization.

33014002340113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36723028247.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 33014002340113 its reverse (31104320041033), we get a palindrome (64118322381146).

The spelling of 33014002340113 in words is "thirty-three trillion, fourteen billion, two million, three hundred forty thousand, one hundred thirteen".

Divisors: 1 29 31 899 36723028187 1064967817423 1138413873797 33014002340113