Base | Representation |
---|---|
bin | 110000001010111000000… |
… | …001000110001110011111 |
3 | 102201110020101002102002011 |
4 | 300022320001012032133 |
5 | 413213303300111221 |
6 | 11012405045412051 |
7 | 461104066466515 |
oct | 60127001061637 |
9 | 12643211072064 |
10 | 3310212113311 |
11 | 1066942493944 |
12 | 45565b40a027 |
13 | 1b01c82849bc |
14 | b63024144b5 |
15 | 5b18d70e1e1 |
hex | 302b804639f |
3310212113311 has 4 divisors (see below), whose sum is σ = 3310217636032. Its totient is φ = 3310206590592.
The previous prime is 3310212113309. The next prime is 3310212113371. The reversal of 3310212113311 is 1133112120133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3310212113311 - 21 = 3310212113309 is a prime.
It is a super-3 number, since 3×33102121133113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3310212113371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1735170 + ... + 3103423.
It is an arithmetic number, because the mean of its divisors is an integer number (827554409008).
Almost surely, 23310212113311 is an apocalyptic number.
3310212113311 is a deficient number, since it is larger than the sum of its proper divisors (5522721).
3310212113311 is an equidigital number, since it uses as much as digits as its factorization.
3310212113311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5522720.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 3310212113311 its reverse (1133112120133), we get a palindrome (4443324233444).
The spelling of 3310212113311 in words is "three trillion, three hundred ten billion, two hundred twelve million, one hundred thirteen thousand, three hundred eleven".
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