Base | Representation |
---|---|
bin | 100101101001001001010000… |
… | …1000101010101010111000101 |
3 | 1121102100211121121002011002000 |
4 | 1023102102201011111113011 |
5 | 321344402414224010341 |
6 | 3132113552014335513 |
7 | 126512634300464112 |
oct | 11322224105252705 |
9 | 1542324547064060 |
10 | 331110321313221 |
11 | 9655810a39799a |
12 | 311774947ba599 |
13 | 1129a752a5a658 |
14 | 5ba9b79d6d909 |
15 | 2842e152b58b6 |
hex | 12d24a11555c5 |
331110321313221 has 8 divisors (see below), whose sum is σ = 490533809352960. Its totient is φ = 220740214208796.
The previous prime is 331110321313217. The next prime is 331110321313273. The reversal of 331110321313221 is 122313123011133.
331110321313221 is a `hidden beast` number, since 3 + 3 + 1 + 1 + 1 + 0 + 321 + 313 + 2 + 21 = 666.
It is not a de Polignac number, because 331110321313221 - 22 = 331110321313217 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 12263345233823 = 331110321313221 / (3 + 3 + 1 + 1 + 1 + 0 + 3 + 2 + 1 + 3 + 1 + 3 + 2 + 2 + 1).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331110321313721) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6131672616885 + ... + 6131672616938.
It is an arithmetic number, because the mean of its divisors is an integer number (61316726169120).
Almost surely, 2331110321313221 is an apocalyptic number.
It is an amenable number.
331110321313221 is a deficient number, since it is larger than the sum of its proper divisors (159423488039739).
331110321313221 is a wasteful number, since it uses less digits than its factorization.
331110321313221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12263345233832 (or 12263345233826 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 331110321313221 its reverse (122313123011133), we get a palindrome (453423444324354).
It can be divided in two parts, 33111032 and 1313221, that added together give a triangular number (34424253 = T8297).
The spelling of 331110321313221 in words is "three hundred thirty-one trillion, one hundred ten billion, three hundred twenty-one million, three hundred thirteen thousand, two hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •