3311111220221 has 4 divisors (see below), whose sum is σ = 3784127108832. Its totient is φ = 2838095331612.

The previous prime is 3311111220149. The next prime is 3311111220251. The reversal of 3311111220221 is 1220221111133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3311111220221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3311111220193 and 3311111220202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3311111220251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236507944295 + ... + 236507944308.

It is an arithmetic number, because the mean of its divisors is an integer number (946031777208).

Almost surely, 2^{3311111220221} is an apocalyptic number.

It is an amenable number.

3311111220221 is a deficient number, since it is larger than the sum of its proper divisors (473015888611).

3311111220221 is an equidigital number, since it uses as much as digits as its factorization.

3311111220221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 473015888610.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 3311111220221 its reverse (1220221111133), we get a palindrome (4531332331354).

The spelling of 3311111220221 in words is "three trillion, three hundred eleven billion, one hundred eleven million, two hundred twenty thousand, two hundred twenty-one".