331113010013 has 4 divisors (see below), whose sum is σ = 348540010560. Its totient is φ = 313686009468.

The previous prime is 331113009979. The next prime is 331113010031. The reversal of 331113010013 is 310010311133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 331113010013 - 2⁸ = 331113009757 is a prime.

It is a super-4 number, since 4×331113010013⁴ (a number of 47 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 331113009973 and 331113010000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (331113610013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8713500245 + ... + 8713500282.

It is an arithmetic number, because the mean of its divisors is an integer number (87135002640).

Almost surely, 2^331113010013 is an apocalyptic number.

It is an amenable number.

331113010013 is a deficient number, since it is larger than the sum of its proper divisors (17427000547).

331113010013 is a wasteful number, since it uses less digits than its factorization.

331113010013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17427000546.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 331113010013 its reverse (310010311133), we get a palindrome (641123321146).

The spelling of 331113010013 in words is "three hundred thirty-one billion, one hundred thirteen million, ten thousand, thirteen".