Base | Representation |
---|---|
bin | 100101101001010100010011… |
… | …0110110100101101000100111 |
3 | 1121102110002211121210011222222 |
4 | 1023102220212312211220213 |
5 | 321400300003322244033 |
6 | 3132132513401342555 |
7 | 126514434132611315 |
oct | 11322504666455047 |
9 | 1542402747704888 |
10 | 331134040431143 |
11 | 965671811a4294 |
12 | 3117bbb4197a5b |
13 | 1129ca62ac0981 |
14 | 5baad8a1710b5 |
15 | 28438527c2598 |
hex | 12d2a26da5a27 |
331134040431143 has 8 divisors (see below), whose sum is σ = 331195767283200. Its totient is φ = 331072314599448.
The previous prime is 331134040431133. The next prime is 331134040431169. The reversal of 331134040431143 is 341134040431133.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 331134040431143 - 210 = 331134040430119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331134040431133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1030642118 + ... + 1030963356.
It is an arithmetic number, because the mean of its divisors is an integer number (41399470910400).
Almost surely, 2331134040431143 is an apocalyptic number.
331134040431143 is a deficient number, since it is larger than the sum of its proper divisors (61726852057).
331134040431143 is a wasteful number, since it uses less digits than its factorization.
331134040431143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510181.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 331134040431143 its reverse (341134040431133), we get a palindrome (672268080862276).
The spelling of 331134040431143 in words is "three hundred thirty-one trillion, one hundred thirty-four billion, forty million, four hundred thirty-one thousand, one hundred forty-three".
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