33120433400042 has 4 divisors (see below), whose sum is σ = 49680650100066. Its totient is φ = 16560216700020.

The previous prime is 33120433400023. The next prime is 33120433400057. The reversal of 33120433400042 is 24000433402133.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 25762131560881 + 7358301839161 = 5075641^2 + 2712619^2 .

It is a junction number, because it is equal to n+sod(n) for n = 33120433399978 and 33120433400014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8280108350009 + ... + 8280108350012.

Almost surely, 2^{33120433400042} is an apocalyptic number.

33120433400042 is a deficient number, since it is larger than the sum of its proper divisors (16560216700024).

33120433400042 is a wasteful number, since it uses less digits than its factorization.

33120433400042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16560216700023.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 33120433400042 its reverse (24000433402133), we get a palindrome (57120866802175).

The spelling of 33120433400042 in words is "thirty-three trillion, one hundred twenty billion, four hundred thirty-three million, four hundred thousand, forty-two".