Base | Representation |
---|---|
bin | 110000001100101000110… |
… | …010001000000100010111 |
3 | 102201122010020000221001212 |
4 | 300030220302020010113 |
5 | 413231142111422403 |
6 | 11013320511412035 |
7 | 461202011414333 |
oct | 60145062100427 |
9 | 12648106027055 |
10 | 3312104014103 |
11 | 1067723407a15 |
12 | 455aa8b2401b |
13 | 1b043a210c21 |
14 | b64417b07c3 |
15 | 5b24e86c4d8 |
hex | 30328c88117 |
3312104014103 has 4 divisors (see below), whose sum is σ = 3325847184528. Its totient is φ = 3298360843680.
The previous prime is 3312104014069. The next prime is 3312104014111. The reversal of 3312104014103 is 3014104012133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3312104014103 - 230 = 3311030272279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3312104014123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6871584851 + ... + 6871585332.
It is an arithmetic number, because the mean of its divisors is an integer number (831461796132).
Almost surely, 23312104014103 is an apocalyptic number.
3312104014103 is a deficient number, since it is larger than the sum of its proper divisors (13743170425).
3312104014103 is a wasteful number, since it uses less digits than its factorization.
3312104014103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13743170424.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 3312104014103 its reverse (3014104012133), we get a palindrome (6326208026236).
The spelling of 3312104014103 in words is "three trillion, three hundred twelve billion, one hundred four million, fourteen thousand, one hundred three".
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